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x-x^2+110=0
We add all the numbers together, and all the variables
-1x^2+x+110=0
a = -1; b = 1; c = +110;
Δ = b2-4ac
Δ = 12-4·(-1)·110
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-21}{2*-1}=\frac{-22}{-2} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+21}{2*-1}=\frac{20}{-2} =-10 $
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